x^2+8x+4.5=0

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Solution for x^2+8x+4.5=0 equation: 



x^2+8x+4.5=0

a = 1; b = 8; c = +4.5;
Δ = b2-4ac
Δ = 82-4·1·4.5
Δ = 46
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(8)-\sqrt{46}}{2*1}=\frac{-8-\sqrt{46}}{2}
$


$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(8)+\sqrt{46}}{2*1}=\frac{-8+\sqrt{46}}{2}
$

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